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Orientation.

Let $ V $ be a real vector space of dimension $ n$. Then define $ \det(V) = \Lambda^n(V)$. This is a real, one dimensional vector space. So the set $ \det(V) = \{0\}$ is disconnected. An orientation of the vector space $ V $ is a choice of one of these connected components. If $ X$ is an invertible linear map from $ V $ to $ V $ then it induces a linear map from $ \det(V) \to \det(V)$ which is therefore multiplication by a complex number. This number is just $ \det(X)$ the determinant of $ X$ If $ M$ is a manifold of dimension $ n$ then the same applies to $ M$; $ \det(T_xM)- \{0\}$ is a disconnected set. We define

Definition 5.2   A manifold is orientable if there is a non-vanishing $ n$-form on $ M$. Otherwise it is called non-orientable.

If $ \eta$ and $ \zeta$ are two non-vanishing $ n$ forms then $ \eta = f \zeta$ for some function $ f$ which is either strictly negative or strictly positive. Hence the set of non-vanishing $ n$ forms divides into two sets. We have

Definition 5.3 (Orientation)   An orientation on $ M$ is a choice of one of these two sets.

An orientation defines an orientation on each tangent space $ T_xM$. We call an $ n$ form positive if it coincides with the chosen orientation negative otherwise. We say a chart $ (U, \psi)$ is positive or oriented if $ d\psi^1\wedge \dots \wedge d\psi^n$ is positive. Note that if a chart is not positive we can make it so by changing the sign of one co-ordinate function so oriented charts exits. If we chose two oriented charts then we have that

$\displaystyle \chi \circ \psi^{-1}_{\vert\psi(U\cap V)}
$

is an oriented diffeomorphism. The converse is also true.

Proposition 5.6   Assume we have a covering of $ M$ by co-ordinate charts $ \{(U_\alpha , \psi_\alpha )\}_{\alpha \in I}$ such that for any two $ (U_\alpha, \psi_\alpha)$ and $ (U_\b , \psi_\b )$ the diffeomorphism

$\displaystyle \psi_\b\circ {\psi_\alpha ^{-1}}_{I\psi_\alpha (U_\alpha \cap U_\b )}
$

is orientation preserving. Then there is an orientation of $ M$ which makes each all these charts oriented.

Proof. Notice that the fact that

$\displaystyle \psi_\b\circ {\psi_\alpha ^{-1}}_{\vert\psi_\alpha (U_\alpha \cap U_\b )}
$

is an oriented diffeomorphism means that if $ x\in U_\alpha \cap U_\b $ then

$\displaystyle d\psi_\alpha ^1\wedge \dots d\psi_\alpha ^n (x)
$

is a positive multiple of

$\displaystyle d\psi_\b ^1\wedge \dots d\psi_\b ^n (x)
$

Hence if $ \phi_\alpha $ is a partition of unity then

$\displaystyle \rho = \sum \phi_\alpha d\psi_\alpha ^1\wedge \dots d\psi_\alpha ^n (x)
$

is a non-vanishing $ n$ form. Clearly this defines the required orientation. $ \qedsymbol$


next up previous contents
Next: Integration again Up: Differential forms. Previous: Integration of differential forms   Contents
Michael Murray
1998-09-16