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Submanifolds again.

If $ M$ is a manifold then we can define a submanifold of $ M$ by using the principal property of submanifolds in $ \mathbb{R}^n$.

Definition 4.4 (Submanifolds.)   We say that a subset $ N \subset M$ is a submanifold of dimension $ d$ of a manifold $ M$ of dimension $ m$ if for every $ x \in N$ we can find a co-ordinate chart $ (U, \psi)$ for $ M$ with $ x \in N$ and such that

$\displaystyle U \cap N = \{ y \in N \colon \mid \psi^{d+1}(y)= \dots = \psi^n(y) = 0\}.
$

Just as before we can define co-ordinates $ (U\cap N, \bar\psi)$ on $ N$ by letting

$\displaystyle \bar\psi^i(y) = \psi^i(y)
$

for each $ i = 1, \dots, d$. Similarly we have

Proposition 4.4   The set consisting of all the charts $ (U\cap N, \bar\psi)$ constructed in this manner is an atlas. Moreover it makes $ N$ a manifold in such a way that the inclusion map $ \iota_N \colon N \to M$ defined by $ \iota_N(n) = n$ is smooth.

Because the condition for being a submanifold is local we can use the inverse function theorem as in Proposition 4.2 to prove

Proposition 4.5   Let $ f \colon M \to N$ be a smooth map between manifolds of dimension $ m$ and $ n$ respectively. Let $ n \in N$ and $ Z = f^{-1}(n)$. Then if $ T_zf$ is onto for all $ z \in M$ the set $ Z$ is submanifold of $ M$. Moreover the image of $ \iota_Z$ in $ T_zM$ is precisely the kernel of $ T_zF$.


next up previous contents
Next: Vector fields. Up: The tangent space. Previous: The tangent to a   Contents
Michael Murray
1998-09-16