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Next: Vector bundles and gauge Up: Line Bundles. Honours 1996 Previous: Curvature as infinitesimal holonomy   Contents

Chern classes

In this section we define the Chern class which is a (topological) invariant of a line bundle. Before doing this we collect some facts about the curvature.

Proposition 3.1   The curvature $ F$ of a connection $ \nabla$ satisfies:
(i)
$ dF = 0$
(ii)
If $ \nabla, \nabla'$ are two connections then $ \nabla =
\nabla' + \eta $ for $ \eta$ a 1-form and $ F_{\nabla} = F_{\nabla'} +
d \eta$.
(iii)
If $ \Sigma $ is a closed surface then $ {\frac{1}{2 \pi i}}
\int_{\Sigma} F_{\nabla}$ is an integer independent of $ \nabla$.

Proof. (i) $ dF\vert _{U \alpha} = d(d A_{\alpha}) = 0.$

(ii) Locally $ A'_{\alpha} = A_{\alpha} + \eta \alpha$ as $ \eta_{\alpha} = A'_{\alpha} - A_{\alpha}$. But $ A_{\beta} =
A_{\alpha} - g_{\alpha \b }^{-1}d g_{\alpha \beta}$ and $ A'_{\beta} =
A'_{\alpha} - g_{\alpha \b }^{-1}d g_{\alpha \beta}$ so that $ \eta_{\beta} = \eta_{\alpha}$. Hence $ \eta$ is a global 1-form and $ F_
{\nabla} = d A_{\alpha}$ so $ F'_{\nabla} = F_{\nabla} + d \eta$.

(iii) If $ \Sigma $ is a closed surface then $ \partial \Sigma =\emptyset$ so by Stokes' theorem $ \int_{\Sigma} F_{\nabla} = \int_{\Sigma} F_{\nabla}'$. Now choose a family of disks $ D_t$ in $ \Sigma $ whose limit as $ t \to 0$ is a point. For any $ t$ the holonomy of the connection around the boundary of $ D_t$ can be calculated by integrating the curvature over $ D_t$ or over the complement of $ D_t$ in $ \Sigma $ and using Proposition 2.1. Taking into account orientation this gives us

$\displaystyle \exp(\int_{\Sigma - D_t} F ) = \exp(- \int_{D_t} F )
$

and taking the limit as $ t \to 0$ gives

$\displaystyle \exp(\int_{\Sigma} F )= 1
$

which gives the required result. $ \qedsymbol$

The Chern class, $ c (L)$, of a line bundle $ L \to
\Sigma$ where $ \Sigma $ is a surface is defined to be the integer $ {\frac{1}{2 \pi i}}
\int_{\Sigma} F_{\nabla}$ for any connection $ \nabla$.

Example 3.1   For the case of the two sphere previous results showed that $ F = - i$   vol$ _{S^2}$. Hence

$\displaystyle c (TS^{2}) = {\frac{- i}{2 \pi i}} \int_{S^{2}}$   vol$\displaystyle =
{\frac{- i}{2 \pi i}} \ 4 \pi = - 2.
$

Some further insight into the Chern class can be obtained by considering a covering of $ S^2$ by two open sets $ U_{0}, U_{1}$ as in Figure 2. Let $ L \to S^{2}$ be given by a transition for $ g_{01} :
U_{0} \cap U_{1} \to {\bf C}^\times$. Then a connection is a pair of 1-forms $ A_{0}$, $ A_{1}$, on $ U_{0}, U_{1}$ respectively, such that

$\displaystyle A_{1} = A_{0} + dg_{10}{g_{10}^{-1}} \ {\mbox {on}} \ U_{0} \cap U_{1}.
$

Take $ A_{0} = 0$ and $ A_{1}$ to be any extension of $ dg_{10}{g_{10}^{-1}}$ to $ U_1$. Such an extension can be made by shrinking $ U_0$ and $ U_1$ a little and using a cut-off function. Then $ F = dA_{0} = 0$ on $ U_0$ and $ F = dA_{1}$ on $ U_1$. To find $ c (L)$ we note that by Stokes theorem:

$\displaystyle \int_{S^2} F = \int_{U_1} F = \int_{\partial U{_1}} A_{1} =
\int_{\partial U_{1}}{dg_{10}g_{10}^{-1}}.
$

But this is just $ 2 \pi i$ the winding number of $ g_{10}$. Hence the Chern class of $ L$ is the winding number of $ g_{10}$. Note that we have already seen that for $ TS^2$ the winding number and Chern class are both $ -2$. It is not difficult to go further now and prove that isomorphism classes of line bundles on $ S^2$ are in one to one correspondence with the integers via the Chern class but will not do this here.

Example 3.2   Another example is a surface $ \Sigma_g$ of genus $ g$ as in Figure 5.

Figure 5: A surface of genus $ g$.
\begin{figure}
\begin{center}
\par\begin{overpic}[scale=.7]{picfive.eps}
\put(10...
...{$U_{g-1}$}
\put(66,0.5){$g$\ holes}
\end{overpic}
\par\end{center}\end{figure}

We cover it with $ g$ open sets $ U_1, \dots, U_g$ as indicated. Each of these open sets is diffeomorphic to either a torus with a disk removed or a torus with two disks removed. A torus has a non-vanishing vector field on it. If we imagine a rotating bicycle wheel then the inner tube of the tyre (ignoring the valve!) is a torus and the tangent vector field generated by the rotation defines a non-vanishing vector field. Hence the same is true of the open sets in Figure 5. There are corresponding transition functions $ g_{12}, g_{23}, \dots, g_{g-1g}$ and we can define a connection in a manner analogous to the two-sphere case and we find that

$\displaystyle c(T\Sigma_g) = \sum^{g - 1}_{i = 1}$   winding number$\displaystyle (g_{i, i + 1}).
$

All the transition functions have winding number $ -2$ so that

$\displaystyle c(T \Sigma_g) = 2 - 2g.
$

This is a form of the Gauss-Bonnet theorem. It would be a good exercise for the reader familiar with the classical Riemannian geometry of surfaces in $ \mathbb{R}^3$ to relate this result to the Gauss-Bonnet theorem. In the classical Gauss-Bonnet theorem we integrate the Gaussian curvature which is the trace of the curvature of the Levi-Civita connection.

So far we have only defined the Chern class for a surface. To define it for manifolds of higher dimension we need to recall the definition of de Rham cohomology [4]. If $ M$ is a manifold we have the de Rham complex

$\displaystyle 0 \to \Omega^{0} (M) \to \Omega^{1} (M) \to . . .
\to \Omega^{m} (M) \to 0.
$

where $ \Omega^{p}(M)$ is the space of all $ p$ forms on $ M$, the horizontal maps are $ d$ the exterior derivative and $ m = \dim (M)$. Then $ d^{2} = 0$ and it makes sense to define:

$\displaystyle H^{p} (M) = {\frac{\hbox{kernel} \ d : \Omega^{p} \ (M) \to \Omega^{p + 1}
\ (M)}{\hbox{image} \ d : \Omega^{p - 1} \ (M) \to \Omega^{p} \ (M)}}
$

This is the pth de Rham cohomology group of $ M$ - a finite dimensional vector space if $ M$ is compact or otherwise well behaved.


The general definition of $ c (L)$ is to take the cohomology class in $ H^{2}
(M)$ containing $ {\frac{1}{2 \pi i}} F_{\nabla}$ for some connection.

It is a standard result [4] that if $ M$ is oriented, compact, connected and two dimensional integrating representatives of degree two cohomology classes defines an isomorphism

$\displaystyle H^{2}(M)$ $\displaystyle \to$ $\displaystyle \mathbb{R}$  
$\displaystyle \left[\omega\right]$ $\displaystyle \mapsto$ $\displaystyle \int_M \omega$  

where $ \left[\omega\right]$ is a cohomology class with representative form $ \omega$. Hence we recover the definition for surfaces.


next up previous contents
Next: Vector bundles and gauge Up: Line Bundles. Honours 1996 Previous: Curvature as infinitesimal holonomy   Contents
Michael Murray
1998-09-16